Give the reaction for the following conversions:
$1$. Ethyne from ethene via bromination
$2$. Bromoethane from ethyne
$1$. Ethyne from ethene via bromination
$2$. Bromoethane from ethyne
(N/A) $1$. Ethyne from ethene:
$CH_2=CH_2 + Br_2$ $\xrightarrow{CCl_4} CH_2Br-CH_2Br$ $\xrightarrow{alc. KOH, \Delta} CH_2=CHBr$ $\xrightarrow{NaNH_2} CH \equiv CH$
$2$. Bromoethane from ethyne:
$CH \equiv CH + 2H_2$ $\xrightarrow{Ni, \Delta} CH_3-CH_3$ $\xrightarrow{Br_2, h\nu} CH_3CH_2Br + HBr$
$CH_2=CH_2 + Br_2$ $\xrightarrow{CCl_4} CH_2Br-CH_2Br$ $\xrightarrow{alc. KOH, \Delta} CH_2=CHBr$ $\xrightarrow{NaNH_2} CH \equiv CH$
$2$. Bromoethane from ethyne:
$CH \equiv CH + 2H_2$ $\xrightarrow{Ni, \Delta} CH_3-CH_3$ $\xrightarrow{Br_2, h\nu} CH_3CH_2Br + HBr$
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Similar Questions
Consider the following reactions:
$(a)$ $CH_3-CH=CH_2 + HBr \rightarrow CH_3-CH(Br)-CH_3$
$(b)$ $CH_3-CH=CH_2 + HBr \xrightarrow{Peroxide} CH_3-CH_2-CH_2Br$
$(c)$ $CH_4 + Cl_2 \xrightarrow{hv} CH_3Cl + HCl$
Which of these reactions proceed via a free radical mechanism?
$(a)$ $CH_3-CH=CH_2 + HBr \rightarrow CH_3-CH(Br)-CH_3$
$(b)$ $CH_3-CH=CH_2 + HBr \xrightarrow{Peroxide} CH_3-CH_2-CH_2Br$
$(c)$ $CH_4 + Cl_2 \xrightarrow{hv} CH_3Cl + HCl$
Which of these reactions proceed via a free radical mechanism?
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